p^2+22pq+120q^2=

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Solution for p^2+22pq+120q^2= equation:


Simplifying
p2 + 22pq + 120q2 = 0

Reorder the terms:
22pq + p2 + 120q2 = 0

Solving
22pq + p2 + 120q2 = 0

Solving for variable 'p'.

Factor a trinomial.
(p + 10q)(p + 12q) = 0

Subproblem 1

Set the factor '(p + 10q)' equal to zero and attempt to solve: Simplifying p + 10q = 0 Solving p + 10q = 0 Move all terms containing p to the left, all other terms to the right. Add '-10q' to each side of the equation. p + 10q + -10q = 0 + -10q Combine like terms: 10q + -10q = 0 p + 0 = 0 + -10q p = 0 + -10q Remove the zero: p = -10q Simplifying p = -10q

Subproblem 2

Set the factor '(p + 12q)' equal to zero and attempt to solve: Simplifying p + 12q = 0 Solving p + 12q = 0 Move all terms containing p to the left, all other terms to the right. Add '-12q' to each side of the equation. p + 12q + -12q = 0 + -12q Combine like terms: 12q + -12q = 0 p + 0 = 0 + -12q p = 0 + -12q Remove the zero: p = -12q Simplifying p = -12q

Solution

p = {-10q, -12q}

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